I2g br2glt---gt2ibrg kc87 x10 to the second at 150 degrees


A) Calculate the molar solubility of mercury (I) bromide?

B) I2(g) + Br2(g)<--->2IBr(g) Kc=8.7 x10 to the second at 150 degrees celcius, Suppose that 0.84 mol of I2 and 0.84 mol of Br2 are placed in a 3.000L flask and allowed to reach equilibrium at 150 degrees celcius. What are the equilibrium concentrations of IBr, I2 and Br2?

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Chemistry: I2g br2glt---gt2ibrg kc87 x10 to the second at 150 degrees
Reference No:- TGS0809443

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