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I our lab we completed conductometric titrations of fecl3

In our lab we completed conductometric titrations of FeCl3 + 6H2O and CuCl2+2H2O causing each of them to undergo double displacement reactions.

I have 2 questions:

If you could manipulate individual molecules and knew that you had 36 molecules of FeCl3, how many molecules of NaOH would you need to completely react with the FeCl3 and how many molecules of each of the products would you form?
What if you had 41 molecules of CuCI2?

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Chemistry: I our lab we completed conductometric titrations of fecl3

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