How much of the cacl2 can be prepared from 385g of an ore


How much of the CaCl2 can be prepared from 385g of an ore containing Ca(OH)2 if the ore is 78.4% Ca(OH)2 by mass? Use the equation: 2 NH4Cl + 1 Ca(OH)2 --> 2 HN3 + 1 CaCl2 + 2 H20

Request for Solution File

Ask an Expert for Answer!!
Chemistry: How much of the cacl2 can be prepared from 385g of an ore
Reference No:- TGS0588532

Expected delivery within 24 Hours