How many moles of o2 were released


Use this data for the questions...
-Mass of tube + MnO2 = 21.5403g
-Mass of tube + MnO2 + KClO3 + KCl = 22.5518g
-Constant mass of test tube + reaction product = 22.3514g

Questions:
1. What is mass of O2 released? (0.2004g)
2. How many moles of O2 were released? (.0063g)
3. How many moles of KClO3 required by the moles of O2 released? (2 moles)
4. What is the mass of KClO3 required? (245.099g)
5. What is the mass of KClO3 & KCl mixture? (.0115g)
6. What is the percent of KClO3 in KClO3 & KCl mixture?
7. If there was 0.5011g of KClO3 in the original mixture, what is the true percent of KClO3? 

Request for Solution File

Ask an Expert for Answer!!
Chemistry: How many moles of o2 were released
Reference No:- TGS0509602

Expected delivery within 24 Hours