How many grams of dipotassium succinate trihydrate


Please determine the right solution of the following Problem

Problem-How many grams of dipotassium succinate trihydrate (K2C4H4O4•3H2O, MW = 248.32 g/mol) must be added to 720.0 mL of a 0.0469 M succinic acid solution to produce a pH of 5.801? Succinic acid has pKa values of 4.207 (pKa1) and 5.636 (pKa2).

I want assist to compute the volume of dipotassium succinate trihydrate.

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