How many grams of dipotassium succinate trihydrate


Please evaluate the answer of the following question

Question- How many grams of dipotassium succinate trihydrate (K2C4H4O4·3H2O, MW = 248.32 g/mol) must be added to 530.0 mL of a 0.0588 M succinic acid solution to produce a pH of 5.966? Succinic acid has pKa values of 4.207 (pKa1) and 5.636 (pKa2).

I need help to compute the quantity of dipotassium succinate trihydrate.

Request for Solution File

Ask an Expert for Answer!!
Other Subject: How many grams of dipotassium succinate trihydrate
Reference No:- TGS0973863

Expected delivery within 24 Hours