Given the following set of reations and their associated heats of reactions calculate delta H for the following reaction: 2NH3(g) + 3N2O(g) ---- 4 N2(g) + 3 H2O(l) a. 4 NH3(g) + 3O2(g) ---- 2 N2 (g) + 6H20 (l) delta H -1531 kj b. N2O(g) + H2(g) --- N2(g) + H2O (l) delta H = -367.4 kj c. H2(g) + 1/2 O2(g) --- H2O(l) delta H= -285.9 kj