Given the above balanced equation with 1010 g of naoh and


1) NaOH(aq) + HCl(aq) → NaCl(aq) +  H2O(l)

Given the above balanced equation. With 1.010 g of NaOH and excess HCl, what mass of NaCl could be formed?

2) Na2CO3(aq) + HCl(aq) → NaCl(aq) + CO2(g) + H2O(l)

Given the above balanced equation. With 1.010 g of Na2CO3 and excess HCl, what mass of NaCl could be formed?

3) Na2O(aq) +  HCl(aq) → NaCl(aq) + H2O(l)

Given the above balanced equation. With 1.010 g of Na2O and excess HCl, what mass of NaCl could be formed?

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Chemistry: Given the above balanced equation with 1010 g of naoh and
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