For the process hno3g hno3l h is -3904 kjmol and s is


For the process: HNO3(g) ? HNO3(l), ΔH° is -39.04 kJ/mol and ΔS° is -111.74 J/(mol · K). What is the normal boiling point of pure HNO3

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Chemistry: For the process hno3g hno3l h is -3904 kjmol and s is
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