Find the equation of motion of the suspended mass


A block of mass mb = 5 kg is suspended from a cable of stiffness k = 300 N/m. The block is acted upon by a vertical force of f(t) = 7sin(8t) [N], where t is in seconds. If the block is pulled down 100 mm from equilibrium and released from rest when the external force begins to act (at t = 0), what is the equation of motion of the suspended mass, y(t)?

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Mechanical Engineering: Find the equation of motion of the suspended mass
Reference No:- TGS0838530

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