A constant torque of 25.0 N · m is applied to a grindstone whose moment of inertia is 0.130 kg · m2. Using energy principles and neglecting friction, find the angular speed after the grindstone has made 15.0 revolutions. (Hint: The angular equivalent of Wnet = FΔx = 1/2 mvf2 - 1/2 mvi2 is Wnet = τΔθ = 1/2 Iωf2 - 1/2 Iωi2. You should convince yourself that this relationship is correct.)