Find nozzle exit area for choked and unchoked


Ramjet Engine
Mach Number=4
Altitude=50,000 ft
T (ambient)=205 K
p=11.6 kPa
h (fuel heating value)=45,000 kJ/kg
T (peak)=3000 K
m (mass flow rate)= 50 kg/s
assume....R=.287 kJ/kgK , ?=1.4 (from state a-->state 3) , ?=1.3 (from state 3-->6)

Diffuser loses:
Stagnation pressure ratio across flame holders (state 2 to 3) =.97
Pressure loss in combustor (state 3->4) is 5%
Nozzle efficiency=.95
combustor efficiency=.98

Calculation needed: Nozzle exit area for choked (converging nozzle) and unchoked (de Laval nozzle)?

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Mechanical Engineering: Find nozzle exit area for choked and unchoked
Reference No:- TGS0733607

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