Explain why molecule has a larger bond angle


A bent molecule a) Methyl azide has the formula CH3N3; the figure on the right shows how the atoms are connected, but not the locations of pi bonds or lone pairs. Draw a Lewis structure for methyl azide, including all bonds, lone pairs, and formal charges. Draw any significant resonance forms. b) What is the hybridization expected for the middle N of the three N atoms in methyl azide? c) The experimentally observed C-Na-Nb bond angle in methyl azide is 117 °, and the bond lengths for Na-Nb and Nb-Nc are 1.24 and 1.13 Å, respectively. Are these measured parameters consistent with your answer in part (a) above? d) If the C-Na-Nb bond angle were forcibly straightened out to 180 °, the methyl azide molecule would become less stable. Why? e) Methyl isocyanate has the formula CH3-N-C-O. The bond angle for the C-N-C bond is 140 °, significantly larger than expected for sp2 hybridization and significantly smaller than expected for sp hybridization. Considering the different resonance structures that contribute to the resonance hybrid in this molecule, explain why this molecule has a larger bond angle than the isoelectronic methyl azide.

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Chemistry: Explain why molecule has a larger bond angle
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