Explain-global existence and uniqueness theorem


Explain the steps on how to solve the problem below:

Express the 2nd order ODE

dt2 u=d2 u/dt2 =sin?(u)+cos?(ωt) ω ∈ Z/{0}

u(0)=a

dtu(0)=b

as a system of 1st order ODEs and verify that there exists a global solution by invoking the global existence and uniqueness Theorem.

Useful information:

Global existence and uniqueness Theorem:

The ordinary differential equation

dtu=f(t,u (t))

u(0)=u–0

has a unique solution if f∈C0 (I)×Lipschitz(L (R)), f is continuous with respect to 1st variable and Lipschitz with respect to 2nd variable.

Lipschitz Continuity: A function g:I→R is Lipschitz continuous if ∃Λ>0 such that ||g(x–)-g(y)||≤Λ||x–y||∀x,y–∈I.

NB: means vector value.

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Engineering Mathematics: Explain-global existence and uniqueness theorem
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