Expalin a central limit theorem


Discuss the below:

Q1. Given the following population data: 1,2,4,5,8,9,12, and the lists of all samples of size 2 and 5:

Samples of n = 2

 

xbar

1,2

1.5

1,4

2.5

1,5

3

1,8

4.5

1,9

5

1,12

6.5

2,4

3

2,5

3.5

2,8

5

2,9

5.5

2,12

7

4,5

4.5

4,8

6

4,9

6.5

4,12

8

5,8

6.5

5,9

7

5,12

8.5

8,9

8.5

8,12

10

9,12

10.5

Samples of

n = 5

 

xbar

1,2,4,5,8

4

1,2,4,5,9

4.2

1,2,4,5,12

4.6

1,2,4,8,9

4.8

1,2,4,8,12

5.4

1,2,4,9,12

5.6

1,2,5,8,9

5

1,2,5,8,12

5.6

1,2,5,9,12

5.8

1,2,8,9,12

6.4

1,4,5,8,9

5.4

1,4,5,8,12

6

1,4,5,9,12

6.2

1,4,8,9,12

6.8

1,5,8,9,12

7

2,4,5,8,9

5.6

2,4,5,8,12

6.2

2,4,5,9,12

6.4

2,5,8,9,12

7.2

4,5,8,9,12

7.6

2,4,8,9,12

7

For population

s = ?
m = ?

For n = 2

sxbar = ?
mxbar = ?

For n = 5

sxbar = ?

mxbar = ?

a) Use Excel to find the six ? values above.

b) Consider the three values of mean and the three values of standard deviation in a). Verify (mathematically) that the Central Limit Theorem applies using the formulas:

µ = µxbar and σxbar = σ / √n

c) Why are your answers from a) and b) slightly off?

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Basic Statistics: Expalin a central limit theorem
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