evaluate following indefinite integrals a int


Evaluate following indefinite integrals.

 (a) ∫ 5t 3 -10t -6 + 4 dt

 (b) ∫ dy

Solution

 (a) ∫ 5t 3 -10t -6 + 4 dt

There's not whole lot to do here other than use the two formulas.  Remember that while integrating powers (which aren't -1 of course) we just add one onto the exponent & then divide through the new exponent.

∫ 5t 3 -10t -6 + 4 dt = 5 ( ¼)  t 4  -10 ( 1/-5) t -5 + 4t + c

= 5/4 t 4 + 2t -5 + 4t + c

Be careful while integrating negative exponents.  Always remember to add one onto the exponent. 

(b) ∫ dy

∫ dy = ∫1dy = y + c

In this case we are actually just integrating a one!

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Mathematics: evaluate following indefinite integrals a int
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