A volume of 80.0 mL of rm H_2O is initially at room temperature (22.0rm{}~^{circ}C). A chilled steel rod at 2.00rm~^{circ}C is placed in the water. If the final temperature of the system is 21.4~^{circ}C, what is the mass of the steel bar?
Use the following values:
specific heat of water = 4.18 rm J/(gcdot{^{circ}C})
specific heat of steel = 0.452 rm J/(gcdot{^{circ}C})