Erythroblastosis fetalis ef is a condition that causes the


Assume that the Rh blood group has only two alleles: the Rh-positive allele (D) and the Rh-negative allele (d).

 Erythroblastosis fetalis (EF) is a condition that causes the mother's red blood cells to attack those of the baby as if they were any foreign invaders. It is referred to as hemolytic anemia of the newborn. It is caused by anti-Rh antibodies from the mother which pass through the placenta and attack fetal blood cells that happen to be Rh-positive. Babies that are at risk for this condition are those with Rh-positive blood, whose mothers are Rh-negative (dd).

 Consider a population under Hardy-Weinberg equilibrium, where the frequency of the Rh-negative allele, d, is 0.3. What is the frequency of crosses that could potentially produce children with erythroblastosis fetalis?

 

Request for Solution File

Ask an Expert for Answer!!
Biology: Erythroblastosis fetalis ef is a condition that causes the
Reference No:- TGS0964867

Expected delivery within 24 Hours