Assignment:
Lead(II) carbonate is very insoluble in water, meaning that the equilibrium constant for the dissociation reaction is much less than 1:
PbCO_3 (s) <-> Pb(2+) (aq) + CO_3(2-) (aq)
Write reactions for each of the following and explain how the equilibrium reaction for the dissociation of lead(II) carbonate is affected.
a. H+ from stomach acid reacts with the carbonate ion
b. Enzymes react with the lead ions to form Pb(enzyme) complexes
c. Lead poisoning can be treated with ethylenediamine (EDTA) which binds with Pb(2+) to form the complex ion [Pb(EDTA)](2=)
d.In order for EDTA administration to be effective, the size of K_eq must be very large for the binding reaction of Pb(2+) with EDTA. Explain why this is.
Provide complete and step by step solution for the question and show calculations and use formulas.