Entropy of van der waals gas


Assignment:

Question 1. Consider n moles of a Van der Waals gas. Show that (dU/dV)_T = n^2a/V^2. Hence show that the internal energy is U = the integral from zero to T of C_vdT - an^2/V + U0 where U0 is a constant. {Hint: Express U = U(T,V)}.

Question 2. As in the previous question, consider n moles of Van der Waals gas. Show that

(a) S = the integral from zero to T of C_v/TdT + nRln(V - nb) + S0
where S0 is a constant. {Hint: Use dS = 1/T(dU + PdV)

(b) The equation for a reversible adiabatic process is
T(V -nb)^(nR/C_v) = a constant
if C_v is assumed to be independent of T.

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Chemistry: Entropy of van der waals gas
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