Assignment:
A sample of 1.500g of gold was analyzed to determine mercury in the same one. It was come by the method of standard addition preparing solution a standard Hg mercury (II) putting under it conditions similar to the one of the sample:
Standard solution: An amount of 50 mg of pure mercury becomes to Hg (II) and is added solvent (H20) until completing 250 mililiter of solution. From this solution an aliquot one of 5 ml is taken and is diluted with solvent up to 100 ml on a volumetric matraz = STOCK
Solution of Sample: The sample of 1.500g of gold was treated, obtaining mercury like Hg (II) and diluted in matraz of 500 ml. Of this solution pull out an aliquot one of 10ml and diluted to 250 ml with solvent in matraz volumetric. This completes is used for the analysis.
The procedure generates the following data:
|
#
|
Vol.Stock (ml)
|
Vol.Sample (ml)
|
Vol. Final with solvent
|
Absorbance
|
|
1
|
0.0 mililiter
|
5,0 mililiter
|
50,0 mililiter
|
0.045
|
|
2
|
1.0
|
5.0
|
50.0
|
0.075
|
|
3
|
2.0
|
5.0
|
50.0
|
0.110
|
|
4
|
3.0
|
5.0
|
50.0
|
0.138
|
|
5
|
5.0
|
5.0
|
50.0
|
0.200
|
|
6
|
8.0
|
5.0
|
50.0
|
0.280
|
a) Determine the mercury concentration (II) in the solution of the analysis.
b) Calculate the concentration of Hg (II) in the solution of sample preparation.
c) Calculate the percentage of Mercury in the solid sample.
Provide complete and step by step solution for the question and show calculations and use formulas.