A Boeing767-300 weighing 275,000 lb is approaching a runway located at sea-level on a clear day with no wind. The FAA landing runway requirement for this aircraft in these conditions is 5000 ft (with auto-brake engaged and flap extension at 25). Instead of using the auto-brake, reverse thrusters will be used. This force can be written as F = - 6v^2 - 6.3*10^5. The airplane should reach taxi speed (4 mph) by the end of the runway. Thus, the relationship between velocity, position of the airplane, and time is as shown below: m(dv/dt) = mv(dv/dx) =- 6v^2 - 6.3*10^5
Part A: (1) Determine the maximum allowable landing velocity. (2) Determine the time until taxi speed is reached at that velocity.
Part B: (1) Determine the maximum allowable landing velocity with a 1.15 factor of safety (FS) applied to the runway length. (2) Determine the time until taxi speed is reached for the 1.15 FS
Make one graph showing velocity vs. position and one graph showing position vs time. Show the results from Part A and Part B on the same graphs.
Print all of the answers to the screen, in a complete sentence, using fprintf.
Each graph should have a title and x,y axis labels. Use different colors for each line. Include a legend.