The electron moves horizontally across the equator of Earth at a speed of 2.50 x 106 m/s and in the direction 35.0° N of E. At this point, the magnetic field of Earth consists of a direction due north, is parallel to the surface, and consists of a value of 3.00 x 10-5 T. Determine the force acting on the electron due to its interaction having the magnetic field of Earth?
i) 6.88 x 10-18 N due west
ii) 6.88 x 10-18 N toward the surface of Earth
iii) 9.83 x 10-18 N toward the surface of Earth
iv) 9.83 x 10-18 N away from the surface of Earth
v) 4.00 x 10-18 N away from the surface of Earth