Determine minimum possible yield strength for single crystal


Consider a single crystal oriented such that the slip direction and normal to the slip plane are at angles 42.7° and 48.3°, respectively, with the tensile axis. If the critical resolved shear stress is 29.3 MPa, what applied stress (in MPa) will be necessary to cause the single crystal to yield? 2. A single crystal of a metal is oriented for a tensile test such that its slip plane normal makes an angle of 65.6° with the tensile axis. Three possible slip directions make angles of 30°, 48°, and 78° with the same tensile axis. (a) Which of these three slip directions is most favored? (b) If plastic deformation begins at a tensile stress of 0.80 MPa (116.0 psi), determine the critical resolved shear stress for this metal. 3. A single crystal of a metal that has the FCC crystal structure is oriented such that a tensile stress is applied parallel to the [100] direction. If the critical resolved shear stress for this material is 0.8 MPa, calculate the magnitude of applied stress necessary to cause slip to occur on the (111) plane in the direction. 4.The critical resolved shear stress for a metal is 25 MPa. Determine the minimum possible yield strength (in MPa) for a single crystal of this metal that is pulled in tension.

Request for Solution File

Ask an Expert for Answer!!
Mechanical Engineering: Determine minimum possible yield strength for single crystal
Reference No:- TGS0725665

Expected delivery within 24 Hours