Derive the frequency equation for the beam


Given \(N=1000 lb, E=30x10^{6} psi, \upsilon=0.3, L=4 ft, \gamma=0.283 lb/in^{3}\) and a 4"x4" hollow square tube beam cross section with a wall thickness of 0.25" :

A) Derive the frequency equation for the beam.

B) Solve the frequency equation for the lowest natural frequency.

C) Show that the frequency in B is lower than the case where there is no axial load.

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Mechanical Engineering: Derive the frequency equation for the beam
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