Construct and interpret a 90 confidence interval for the


A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.49 ?hours, with a standard deviation of 2.47 hours. A random sample of 40 adults with children under the age of 18 results in a mean daily leisure time of 4.35 ?hours, with a standard deviation of 1.58 hours. Construct and interpret a 90?% confidence interval for the mean difference in leisure time between adults with no children and adults with children left parenthesis mu 1 minus mu 2 right parenthesis.

Let mu 1 represent the mean leisure hours of adults with no children under the age of 18 and mu 2 represent the mean leisure hours of adults with children under the age of 18.The 90?% confidence interval for left parenthesis mu 1 - mu 2 right parenthesis is the range from (  ) hours to (  ) hours.

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Business Economics: Construct and interpret a 90 confidence interval for the
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