Consider the probability distribution of the time worker two takes to complete all tasks once. Assume walking times are normally distributed with same mean and variance as the triangularly distributed times. The mean and variance of a triangular distribution are computed as follows:
a. The time for worker two to complete all tasks once is normally distributed. Compute the mean and standard deviation of this distribution. Assume that the minimum is 75% of the mean and the maximum is 125% of the mean as stated on page 11-5. Thus, the distribution is symmetric implying mean = mode
b. What is the probability that the time to complete all tasks once is greater than the takt time?