Consider the following balanced equation 6hclaq 2als 3h2g
Consider the following balanced equation: 6HCl(aq) + 2Al(s) → 3H2(g) + 2AlCl3(s)
If 16.2 moles of HCl(aq) and 6.09 moles of Al(s) are allowed to react, and the percent yield is 68.5%, how many moles of H2(g) will actually be produced?
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