Compute volume of titrant needed-second equivalence point


1) Calculate the volume of 0.150 M NaOH titrant added to 50.00 mL of a 0.0100 M HCl analyte solution to produce a pH of: 2.00, 2.11, 7.00, and 11.60.

2) A 100.0 mL solution of 0.5 M histidine in its tribasic form, A3-, (pKa1 = 1.70, pKa2 = 6.02, pKa3 = 9.08) is titrated with 1.0 M HCl titrant.

(a) calculate the volume of titrant required to reach the second equivalence point,

(b) calculate the pH after the addition of 50.0 mL of titrant,

(c) calculate the pH after the addition of 62.0 mL of titrant,

(d) calculate the pH after the addition of 75.0 mL of titrant.

 

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Chemistry: Compute volume of titrant needed-second equivalence point
Reference No:- TGS0540707

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