Compute total pressure drop in system-power of sea water


City water will be cooled in a heat exchanger by sea water entering at 15oC. The outlet temperature of the sea water is 20oC. City water will be recirculated to reduce water consumption. The suction line of the pump has an inner diameter of 154 mm, is 22 m long, and has two 90° bends and a hinged check valve. The pipe from the pump to the heat exchanger has an inner diameter of 127 mm, is 140 m long, and has six 90° bends. The 90° bends are all made of steel with a radius equal to the inner diameter of the pipe, R/d = 1.0. The heat exchanger has 62 tubes in parallel, each tube is 6 m long. The inner diameter of the tubes is 18 mm. All pipes are made of drawn mild steel. The sea water flow rate is 120 m3 /h. Assume that there is one velocity head loss at the inlet and 0.5 velocity head loss at the outlet of the heat exchanger. The elevation difference is 10.5 m.
Calculate:
a. The total pressure drop in the system (kPa and m liquid head = H m)
b. The power of the sea water pump

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Mechanical Engineering: Compute total pressure drop in system-power of sea water
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