Compound a is c4h9cl and shows two 13c nmr resonances


Compound A is C4H9Cl and shows two 13C NMR resonances. Compound B is an isomer of compound A; it shows four 13C NMR resonances, and in the spin-coupled mode the resonance farthest downfield is a doublet. Identify compound A

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Chemistry: Compound a is c4h9cl and shows two 13c nmr resonances
Reference No:- TGS0614341

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