Calculating the enthalpy change


Calculate the enthalpy change for the following reaction.

4 CHCl3 (l) + 5 O2 (g) ---> 4 CO2 (g) + 2 H2O (l) + 6 Cl2 (g)

Substance ----> H°f (kJ / mol)

CHCl3 (l) -132

CO2 (g) -393.5

H2O (l) -285.8

a. -8.11 x 102 kJ

b. -5.48 x 102 kJ

c. 1.62 x 103 kJ

d. 5.48 x 102kJ

e. -1.62 x 103 kJ

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Chemistry: Calculating the enthalpy change
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