Calculate the value of the equilibrium constant for the reaction that occurs when solid sodium oxalate is dissolved in water.
Ka for oxalic acid =
3.78 x 10-6
H2 C2 O4 ------2H+ + C2O4-2
Original oxalate ion concentration was 5.68 x 10-7
PH of 0.015 M oxalic acid solution is 0.5