A compound contains only carbon, hydrogen, and oxygen. Combustion of 23.42 g of the compound yields 34.33 g of CO2 and 14.05 g of H2O.
The molar mass of the compound is 180.156 g/mol.
*Each part of this problem should be submitted separately to avoid losing your work*
1. Calculate the grams of carbon (C) in 23.42 g of the compound: ?grams
2. Calculate the grams of hydrogen (H) in 23.42 g of the compound. ?grams
3. Calculate the grams of oxygen (O) in 23.42 g of the compound. ?grams
Based on your previous answers, calculate
1. the moles of carbon (C) in 23.42 g of the compound: ?moles
2. the moles of hydrogen (H) in 23.42 g of the compound: ?moles
3. the moles of oxygen (O) in 23.42 g of the compound: ?moles
Divide each mole quantity that you determined in the previous question by the smallest number of moles to determine the correct empirical formula.
Enter the correct subscript for each atom using the smallest whole number.
Enter a 1 if that is the smallest whole number, don't leave the box empty. C_ H_ O_
Now determine the molecular formula. Remember that the molar mass of the compound is 180.156 g/mol.
Enter the correct subscript for each atom using the smallest whole number.
Enter a 1 if that is the smallest whole number, don't leave the box empty.
C_ H_ O_