A mixture of 0.04289 mol of O2, 0.09388 mol of NOCl, 0.04841 mol of NO2, and 0.05516 mol of Cl2 is placed in a 1.0-L steel pressure vessel at 1082 K. The following equilibrium is established: 1 O2(g) + 2 NOCl(g) <=> 2 NO2(g) + 1 Cl2(g) At equilibrium 0.03204 mol of O2 is found in the reaction mixture. (a) Calculate the equilibrium partial pressures of O2, NOCl, NO2, and Cl2. Peq(O2) = . Peq(NOCl) = . Peq(NO2) = . Peq(Cl2) = . (b) Calculate KP for this reaction. KP