Blanks are arriving with exponential interarrival time


(a) In a small job shop, there are a lathe and drill operations. Blanks are arriving with exponential interarrival time with mean 1.1 (time units are in minutes). After arrival, blanks are classified as lathe or drill. While 80% of them of them are classified as Drill the rest is classified for the lathe machine. Blanks next go to one of the four labelers in random. They work in parallel with same performance measure and there is one queue in front of the four labelers. It takes triangular (2.5, 3.5, 4) minutes to label each blank.

Each Blank next goes to either drill or lathe based on their label. For the lathe machine, there is one server and it takes triangular (2.5, 3.5, 5) minutes. There are two parallel resources for the drill machine with one queue and it takes (1.5, 2.0, 2.5) triangular to drill each blank. The operators are working 8 hours per day. Each operator takes a rest time of 15 minutes two hours after they start. Their lunch time is 30 minutes at noon, -in the middle of the day. Two hours after lunch they again take a break of 15 minutes.

1. Use wait break rule and calculate number of parts produced. Animate your model. Plot number of blanks in each of the three queues in the animation. Run the model for 10 days.
2. Submit arena model (preferably, latest use free student version), and briefly explain how each model is used (such as create model with inter-arrival time of EX(1) minutes).

(b) Use three different break rules and compare the results if there is a significant change in number of parts produced using these three different rules (Wait, Ignore or Preempt Rules). 

1. Use only Minitab results for comparison purpose.
2. What is the conclusion. Explain.  

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Mechanical Engineering: Blanks are arriving with exponential interarrival time
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