Bases molarity of a solution


Assignment:

Q1. 0.54 g of ammononium chlordie is dissolc=ved in 250 mL of solution. Calculate the molarity.

Q2. What volumne of solution would be required to deliver 6.84 g og 0.200 M aluminum sulfate solution?

Q3. Calculate the molarity of a solution if 126 mL of 6.25 M NaOH was diluted to a total volume of 250mL.

Q4. Calculate the pH of a solution with [H+] = 1.35 x 10-2(-2 is superscript)M. State whether the solution is an acid or a base. Why?

Q5. Calculate the hydorgen ion concentration of a colution with a pH of 2.4.

Q6. If 25 mL of a 0.45 M AgNO3 solution is added to an excess of a 1.2 M NaCl solution, what mass of AgCl will be preciptitated?

AgNO3(aq) + NaCl(aq) -> AgCl(s) + NaNO3(aq)

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Chemistry: Bases molarity of a solution
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