At load step n 1 incremental strain deltaepsilon12nbsp


A pure shear deformation is applied to the square element as shown in the figure such that σ12 = σ21 is only nonzero stress component.

At load step n, the stress value was σ12 = 50, and there was no plastic deformation. At load step n + 1, incremental strain Δε12 = Δε21 = 0.005 is applied. Calculate stress components andeffective plastic strainatload step n + 1.

Use the following material properties: shear modulus μ = 1,000, plastic modulus H = 100, initial yield stress σY = 100.

1854_Fig 6.jpg

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