assume the following parameters: Mass of the bottom steel disc: 1.4678 kg Mass of the upper steel disc: 1.4795 kg Mass of the upper aluminum disc: 0.4614 kg Radius of each disc: 63.3 mm Radius of the take-up spool: r = 125 cm Mass of the falling weight: 25 grams 1. Using the values given above, calculate the following: a) The moment of inertia of the lower, steel disc b) The moment of inertia of the upper, steel disc c) The moment of inertia of the upper, aluminum disc d) The combined moment of inertia of the two steel discs Which I found to be 2940.7kg mm^2, 2964.1kg mm^2, 924.39kg mm^2, and 5904.75kg mm^2 2.Using the results of problem 1, what percentage error is made by neglecting mr^2 with respect to I in the equation (mgr)/(mr^2+I) where I= Inertia 3. Suppose the counter is reading 400 counts per second at at some moment. What is the value of omega at that moment?