Assume that an inexpensive watch runs 0004 slower than a


Assume that an inexpensive watch runs 0.004% slower than a "perfect watch" (viz., a "time standard") that neither loses nor gains time. That inexpensive watch measures a time interval as Delta t = 5 days 1 hours 44 minutes 11 seconds ± 0.7 seconds, where the quoted uncertainty in time comes from the measurement procedure, not from the watch itself. Assuming that the same measurement procedure is used, what would the perfect watch measure for this time interval? Give the answer in seconds to the nearest 0.1 s. Also give the uncertainty in seconds to the nearest 0.1 second.

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Physics: Assume that an inexpensive watch runs 0004 slower than a
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