Solve the all parts of given question:
Question: An inquisitive physics student and mountain climber climbs a 52.1 m cliff that overhangs a calm pool of water. He throws two stones vertically downward, 1.35 s apart and observes that they cause a single splash. The first stone has an initial velocity of 2.2 m/s.
Part I: How long after release of the first stone do the two stones hit the water?
Part II: What is the initial velocity of the second stone if the two stones hit simultaneously?
Part III: What is the speed of each stone when it hits the water, Enter the slower speed first.
I don't just need an answer, work and explanations/walkthrough would be much appreciated! Thanks.