Acircular hole of radius 8470times10minus1 cm must be cut


Engineering Application Acircular hole of radius 8.470×10−1 cm must be cut into the front panel of a display unit. The tolerance is1.0×10−3 cm, which means the actual hole cannot differ by more than this quantity fromthe desired radius. If the actual holeis larger than the desired radius by the allowed to lerance,what is the difference between the actual area and the desired area of the hole?

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Physics: Acircular hole of radius 8470times10minus1 cm must be cut
Reference No:- TGS0824421

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