A student is running her top speed of 48ms to catch a bus


Compute each part og given question:

Question: A student is running her top speed of 4.8m/s to catch a bus, which is stopped at the bus stop. When the student is still a distance 39.7m from the bus, it starts to pull away, moving with a constant acceleration of 0.166m/s2.

Part I: For how much time does the student have to run at 4.8m/s before she overtakes the bus?

t = ____ s

Part II: For what distance does the student have to run at 4.8m/s before she overtakes the bus?

d = ___ m

Part III: When she reaches the bus, how fast is the bus traveling?

v = ___ m/s

Part IV: If the student's top speed is 2.80m/s, will she catch the bus?

Yes/No.

Part V: What is the minimum speed the student must have to just catch up with the bus?

v = ___ m/s

Part VI: For what time does she have to run in that case?

t = ___ s

Part VII: For what distance does she have to run in that case?

d = ___ m

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Physics: A student is running her top speed of 48ms to catch a bus
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