A spring of spring constant k 8250 nm is displaced form


Question 1 A spring of spring constant k = 8.250 N/m is displaced form equilibrium by a distance of 0.1500 m. If the spring is strected form the displacement of 0.1500 m to a displacement of 0.3500 m, what is the change in spring potential energy between those two positions?

Question 2 A spring of spring constant k=12.50 N/m is hung vertically. A 0.500kg mass is then suspended from the spring. What is the displacement of the end of the spring due to the weight of the 0.500kg mass?

Question 3 A mass of 0.4000 kg is rasised by a vertical distance of 0.4500 in the earth's gravitational field. What in the change in its gravitational potential energy? This same mass is lowered by a vertical distance of 0.3500m in the earth's gravitational field. What is the change in its gravitational potential energy?

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Physics: A spring of spring constant k 8250 nm is displaced form
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