Solve the all parts of given problem:
Problem: A sky diver of mass 53 kg can slow herself to a constant speed of 92 km/h by orienting her body horizontally, looking straight down with arms and legs extended. In this position, she presents the maximum cross-sectional area and thus maximizes the air-drag force on her.
Part A: What is the magnitude of the drag force on the sky diver?
Part B: If the drag force is equal to bv2, what is the value of b?
Part C: At some instant she quickly flips into a "knife" position, orienting her body vertically with her arms straight down. Suppose this reduces the value of b to 50 percent of the value in Parts (a) and (b). What is her acceleration at the instant she achieves the "knife" position?
I need help to find the magnitude of the drag force on the sky diver.