A sealed tube contains 166 atm pcl5 at 500 k the pcl5


A sealed tube contains 1.66 atm PCl5 at 500 K. The PCl5 decomposes until equilibrium is established. The equilibrium pressure in the tube is 2.28 atm. Calculate Kp for this equilibrium.

PCl5(g) PCl3(g) + Cl2(g)

First off, do I take the reciprocal again since this is a decomposition reaction?

PCl3 + Cl2/ PCl5 ? If so what are the numerical values? I am not getting the same answer as my friend.

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Chemistry: A sealed tube contains 166 atm pcl5 at 500 k the pcl5
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