A packed tower is designed to recover 98 co2 from a gas

Question

QUESTION - 2 A packed tower is designed to recover 98% CO₂ from a gas mixture containing 10 % CO₂ and 90 % air using water . A relation y = 14 x can be used for equilibrium conditions where y is kg CO₂ / kg dry air and x is kg CO₂ /kg water. The water to gas rate is kept 30 % more than the minimum value . the height of the tower ,if (HTU )o4 = 1 meter ,will be Solution - Y₁ =10/90 =0.111 Y₂ = 10/90*0.02 =0.0022 X2 =0 Y = y =14x In mole fraction term - Y /44 /1/29 =14 *x/44 /1/18 For minimum liquid rate , X₁ = Y₁/8.69 = 0.0128 G ( Y1 - Y2) = Lmin * X1 Lmin = ( Y_I-Y₂)* G/X₁ = 0.1111 -0.0022 / 1.3 *0.0128 = 8.5 Hence , liquid concentration = Y₁-Y₂/11.05 = 0.0098 Ye₁ = 8.69 *X1 = 8.69 *X1 =8.69 *0.0098 =0.085 NTUs = 0.1111 -0.0022/ ( 0.1111-0.085) - ( 0.0022 -0) / ln {0.1111-0.085 /0.0022} = 11.29 Height = HTU *NTU = 1*11.29 =11.29 m Height = HTU *NTU = 1*11.29 =11.29 m to recover 98% CO₂ from a gas mixture containing 10 % CO2 and 90 % air using water . A relation y = 14 x can be used for equilibrium conditions where y is kg CO₂ / kg dry air and x is kg CO₂ /kg water. The water to gas rate is kept 30 % more than the minimum value . the height of the tower ,if (HTU )o4 = 1 meter ,will be Solution - Y₁ =10/90 =0.111 Y2 = 10/90*0.02 =0.0022 X₂ =0 Y = y =14x In mole fraction term - Y /44 /1/29 =14 *x/44 /1/18 For minimum liquid rate , X₁ = Y₁/8.69 = 0.0128 G ( Y₁ - Y₂) = Lmin * X₁ Lmin = ( Y_I-Y₂)* G/X₁ = 0.1111 -0.0022 / 1.3 *0.0128 = 8.5 Hence , liquid concentration = Y₁-Y₂/11.05 = 0.0098 Ye1 = 8.69 *X1 = 8.69 *X₁ =8.69 *0.0098...