Part 1:
1) Explain pure bending moment and assumptions in the theory of pure bending.
2) Derive the equation of bending stress.
3) Explain moment of resistance and some simple beams equation.
4) A rectangular section 600 mm deep is used as a simply supported beam of length 6.0 m . the beam carries a central point load of 200 1m • find maximum bending stress induced in the section. take !xx = 1.33 x 10"9 mm4.
5) A cantilever beam 4 m span is subjected to udl 20 kn/ m over entire span and a point load of 40 1m at free end. The section of beam is rectangular having depth eqal to twice the width. If bending stress is not to exceed 100 n/mm2. Decide dimension of the beam.
6) A mild steel plate 100 mm wide and 12 mm thick is subjected to B. M of 600 N.M. find radius of arc and maxi. Bending stress due to this B.M on plate. Take modulus of elasticity=E= 2 X 10"5 N/mm2
Part 2: COLUMN AND STRUT
1) Difference between strut and column.
2) Define a) radius of gayration b) slanderness ratio c) long column d) short column e)crushing load f) crippling load and its euler's formula and assumpations g) renkine's formula.
3) A column of height 10m is rlXed at one and hinged at the other enD. The cross section of the column is a hollow sqare of external size 600 mm and internal size 400mm. determine the safe load column can carry by using eular's formula. Take E = 2X 10"5 N/mm2 and factor of safety =2.
4) A rectangular column of M.S. 300 mm x 400 mm is rlXed at both ends. The length of column is 6 m. calculate euler's load. take E = 2 x 10"5 /mm2.
5) A hollow steel tube of 25 mm external diameter and 20 mm internal diameter is used as a column 3 m long with both ends hinged. Determine the euler's crippling load if modulus of elasticity is 2 x 10"5 N/mm2.
6) Compare the strength of solid circular and hollow circular column using euler's formula. For hollow column internal diameter is 7/10 times the external diameter. Both the columns have same cross section area, same length, same material and honged at botjh ends.
7) A hollow circular column 2.8 m long is hinged at both ends. It buckles at 585 1m load. If E =1.6 x 10"5 N/mm2 and external diameter is 1.25 times the internal diameter, find both the diameter of olumn.
8) A 4 m long pipe having one end fixed and other end hinged is used as a column. It has outer diameter 40 mm and thickness 10 mm. for pipe material E = 2 x 10"5 N/ mm 2 and fc = 320 n/mm2. Find a) buckling load by euler's formula b) crippling load by renkine formula. .
9) A steel column 4 m long i {"lXedat both ends. Calculate the safe load carries by the column by euler's formula. Take !xx = 1.98 x 10 "8 mm4 , Iyy = 2.51 x 10"7 mm4, E =2 x 10"5 N/mm2 and F.O.S = 4.
Part 3: MECHANICAL PROPERTIES OF MATERIAL
1) List the engineer materials used as machine elements.
2) List THE testing of materials and draw a neat and clean sketch.
3) Difference between the terms: a) elasticity and plasticity. b) Ductility and brittleness. c) resilience and toughness. d) malleability and ductility.
4) classification of engineering materials based on physical properties
Part 4: DEFLECTION OF BEAM
1) Define slope and deflection wih figure and equation.
2) An u.d.1. of 40 kn/m is acting on a cantilever beam of length 4.0 m. calculate the slope and deflection of the beam at the free end. E=2 x10 1\5 N/mm2 and I =200 cm4.
3) A 3.0 m long cantilever is having 200mm width and 300 mm depth carrinng point load at free end. If deflection at free and is 8 mm. calculate point load at free end. e = 2 x 101\5 N/ mm2.
4) A simply supported beam 5 m in span is subjected of u.d.l. of 20 kn/m over entire span with central point load of 7 kn. The cross section of beam is 200 mm wide x 350 mm depth. Calculate the maximum slope and deflection for the beam.
5) A simply supported beam of span 3.0 m is subjected to a central load of 20 kn. Find the slope and deflection of the beam. If E= 2 x 101\5 N/mm2 and I = 1.20 x 101\5 mm4.
6) A cantilver beam '6m long is subjected an UDL of 18 kn/m over entire span. IF deflection at free end is zero. Find upward point load required at free end.
7) Cross section of wooden beam is 200 x 310 mm. it is simply supported with 6 m span. Find out UDL that can be placed on its full span so that deflection is 8 mm. E = 0.11 x 101\5 N/mm2.
Part 5: COMBINED DIRECT AND BENDING STRESS
1) DIFFERENCEBETWEEN Axial load and eccentric load.
2) Explain 1) limit of eccentricity 2) no tension condition 3) core of sectionor kernel.
3) Draw core for the following sections. 1) RECTANGULAR 2) CIRCULAR 3) HOLLOW RECTANGULAR 4) HOLLOW CIRCULAR 5) T SECTION 5) I SECTION.
4) A rectangular column 250 mm x 400 mm in size carrying 12 kn load on axis bisecting the thickness wih eccentricity of 60 mm. calculate maximum and minimum stresses in the material.
5) A hollow circular column having external and i"nternal diameter 300 mm and 250 mm respectively. A load of 10 kn is acting on its outer edge. Find maximum and minimum stresses in the section. Also draw stress distribution diagram.
6) A load of 200 kn is acting on a column 400 mm x 300 mm size at eccentricity 'e' on axis bisecting 300 mm side. If maximum safe stress is 4 N/mm2. Find value 'e'.
7) Draw core diagram for a rectangular section of size 350 mm x 200 mm.
8) A hollow rectangular column at external dimensions 300 x 220 mm. the thickness of column is 40 mm. a vertical load of 30 kn acts on at an eccentricity of 36 mm from C.g. of the section in a plane bisecting shorter side. Find the maximum and minimum intensities of stress at the base.
9) Draw core for hollow circular section having 400 mm extranal and 320 mm internal.
10) A rectangular colur:nn size 400 mm x 300 mm is subjected to two equal point loads 300 kn each one at 40 mm & other 60 mm away from centroid on longer side axis. Draw stress distribution diagram on each side of column.