A dilute aqueous solution of calcium hydroxide at 25 C reacts with gaseous hydrogen chloride via the following reaction: 2HCl(g) + Ca(OH)_2 (aq, r= infinity) --> CaCl_2 (aq, r= infinity) + 2H_2O(l)
If the hydrogen chloride enters the reactor at 88.0°C, and the solution exits at 25°C, how much heat must be removed for every mole of CaCl2 produced? The heat of solution of Ca(OH)2 is -1008.2 kJ/mol, the heat of formation of Ca(OH)2 is -985.65 kJ/mol, the heat of solution of CaCl2 is -875.07 kJ/mol and the heat of formation of CaCl2 is -797.46 kJ/mol.
Hint: You will need to find the heat of formation of both liquid water and gaseous hydrogen chloride. These values may be found in your text or another resource.