A cube of lead density 113 x 103 kgm cubed is placed in a


1) Carbon Monoxide is a toxic pollutant found in our city air. On a particular day, the air contains 6.50 mg of CO per 1.000 X 10^3 cubic meter of air. How many grams of CO are present in a room whose dimensions are 15.0 meters x 11.0 meters X16.5 meters? Show steps and also unit conversions within steps (e.g. what did you multiply or divide by to convert 6.50 mg to kg?).

2) Archimedes' principle states that when an object is immersed in a fluid, the buoyant force is equal to the weight of the fluid displaced by object. The weight of an object is equal to its mass times the acceleration due to gravity. Therefore, the weight of the fluid displaced is equal to the volume of the fluid displaced times the density of the fluid times the acceleration due to gravity. Weight (N, Newtons) = mass (kg) X g. At sea level, g = 9.81 m/s squared. 

Question: A cube of lead (density = 11.3 X 10^3 kg/m cubed) is placed in a pool of mercury (density = 13.6 X 10^3 kg/m cubed). The cube of lead is 3.60 X 10^2 cm on a side. Calculate the percentage of the cube that is above the pool of mercury. Show unit conversions and complete formulas while solving for grams of CO present in the room. 

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Chemistry: A cube of lead density 113 x 103 kgm cubed is placed in a
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